Base | Representation |
---|---|
bin | 1100111010100111101110… |
… | …0000101000001000100111 |
3 | 1212021121212102020220202002 |
4 | 3032221323200220020213 |
5 | 3330133111402444033 |
6 | 50111542402435515 |
7 | 2664001550401025 |
oct | 316517340501047 |
9 | 55247772226662 |
10 | 14201234031143 |
11 | 4585789426735 |
12 | 1714364662b9b |
13 | 7c022ab21363 |
14 | 3714b43bb715 |
15 | 1996178813e8 |
hex | cea7b828227 |
14201234031143 has 2 divisors, whose sum is σ = 14201234031144. Its totient is φ = 14201234031142.
The previous prime is 14201234031067. The next prime is 14201234031151. The reversal of 14201234031143 is 34113043210241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14201234031143 - 210 = 14201234030119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14201234033143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7100617015571 + 7100617015572.
It is an arithmetic number, because the mean of its divisors is an integer number (7100617015572).
Almost surely, 214201234031143 is an apocalyptic number.
14201234031143 is a deficient number, since it is larger than the sum of its proper divisors (1).
14201234031143 is an equidigital number, since it uses as much as digits as its factorization.
14201234031143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 14201234031143 its reverse (34113043210241), we get a palindrome (48314277241384).
The spelling of 14201234031143 in words is "fourteen trillion, two hundred one billion, two hundred thirty-four million, thirty-one thousand, one hundred forty-three".
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