142014011 has 2 divisors, whose sum is σ = 142014012. Its totient is φ = 142014010.

The previous prime is 142014001. The next prime is 142014017. The reversal of 142014011 is 110410241.

It is a strong prime.

It is an emirp because it is prime and its reverse (110410241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 142014011 - 2⁶ = 142013947 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (142014017) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71007005 + 71007006.

It is an arithmetic number, because the mean of its divisors is an integer number (71007006).

Almost surely, 2^142014011 is an apocalyptic number.

142014011 is a deficient number, since it is larger than the sum of its proper divisors (1).

142014011 is an equidigital number, since it uses as much as digits as its factorization.

142014011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32, while the sum is 14.

The square root of 142014011 is about 11916.9631618127. The cubic root of 142014011 is about 521.7275029451.

Adding to 142014011 its reverse (110410241), we get a palindrome (252424252).

The spelling of 142014011 in words is "one hundred forty-two million, fourteen thousand, eleven".