Base | Representation |
---|---|
bin | 10100101010101001111… |
… | …011011011000010000011 |
3 | 12000202202111021220002112 |
4 | 110222221323123002003 |
5 | 141232022133300103 |
6 | 3004232031205535 |
7 | 204414430651445 |
oct | 24525173330203 |
9 | 5022674256075 |
10 | 1420190134403 |
11 | 4a8332341087 |
12 | 1ab2aa9768ab |
13 | a3c007c3471 |
14 | 4ca47c66495 |
15 | 26e20936cd8 |
hex | 14aa9edb083 |
1420190134403 has 2 divisors, whose sum is σ = 1420190134404. Its totient is φ = 1420190134402.
The previous prime is 1420190134387. The next prime is 1420190134457. The reversal of 1420190134403 is 3044310910241.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1420190134403 - 24 = 1420190134387 is a prime.
It is a super-2 number, since 2×14201901344032 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1420190134403.
It is not a weakly prime, because it can be changed into another prime (1420190134303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710095067201 + 710095067202.
It is an arithmetic number, because the mean of its divisors is an integer number (710095067202).
Almost surely, 21420190134403 is an apocalyptic number.
1420190134403 is a deficient number, since it is larger than the sum of its proper divisors (1).
1420190134403 is an equidigital number, since it uses as much as digits as its factorization.
1420190134403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 32.
The spelling of 1420190134403 in words is "one trillion, four hundred twenty billion, one hundred ninety million, one hundred thirty-four thousand, four hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.081 sec. • engine limits •