14202340013401 has 2 divisors, whose sum is σ = 14202340013402. Its totient is φ = 14202340013400.

The previous prime is 14202340013383. The next prime is 14202340013413. The reversal of 14202340013401 is 10431004320241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13543312655376 + 659027358025 = 3680124^2 + 811805^2 .

It is a cyclic number.

It is not a de Polignac number, because 14202340013401 - 2¹⁹ = 14202339489113 is a prime.

It is a super-3 number, since 3×14202340013401³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (14202340013461) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7101170006700 + 7101170006701.

It is an arithmetic number, because the mean of its divisors is an integer number (7101170006701).

Almost surely, 2^{14202340013401} is an apocalyptic number.

It is an amenable number.

14202340013401 is a deficient number, since it is larger than the sum of its proper divisors (1).

14202340013401 is an equidigital number, since it uses as much as digits as its factorization.

14202340013401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 14202340013401 its reverse (10431004320241), we get a palindrome (24633344333642).

The spelling of 14202340013401 in words is "fourteen trillion, two hundred two billion, three hundred forty million, thirteen thousand, four hundred one".