Base | Representation |
---|---|
bin | 10100101010101100100… |
… | …010110101010100011011 |
3 | 12000202212112212111222120 |
4 | 110222230202311110123 |
5 | 141232114402120443 |
6 | 3004240235552323 |
7 | 204415502662242 |
oct | 24525442652433 |
9 | 5022775774876 |
10 | 1420234020123 |
11 | 4a8355096076 |
12 | 1ab3015bb6a3 |
13 | a3c0991a849 |
14 | 4ca4da0b959 |
15 | 26e24705083 |
hex | 14aac8b551b |
1420234020123 has 12 divisors (see below), whose sum is σ = 1934792937000. Its totient is φ = 926677512352.
The previous prime is 1420234019987. The next prime is 1420234020131. The reversal of 1420234020123 is 3210204320241.
It is a happy number.
It is not a de Polignac number, because 1420234020123 - 221 = 1420231922971 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1420234020093 and 1420234020102.
It is not an unprimeable number, because it can be changed into a prime (1420234020173) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 107148498 + ... + 107161751.
It is an arithmetic number, because the mean of its divisors is an integer number (161232744750).
Almost surely, 21420234020123 is an apocalyptic number.
1420234020123 is a deficient number, since it is larger than the sum of its proper divisors (514558916877).
1420234020123 is an equidigital number, since it uses as much as digits as its factorization.
1420234020123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 214310346 (or 214310299 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 24.
Adding to 1420234020123 its reverse (3210204320241), we get a palindrome (4630438340364).
The spelling of 1420234020123 in words is "one trillion, four hundred twenty billion, two hundred thirty-four million, twenty thousand, one hundred twenty-three".
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