Base | Representation |
---|---|
bin | 10100101010101100100… |
… | …011111110100101011111 |
3 | 12000202212120102202122101 |
4 | 110222230203332211133 |
5 | 141232114441221343 |
6 | 3004240250225531 |
7 | 204415505352205 |
oct | 24525443764537 |
9 | 5022776382571 |
10 | 1420234320223 |
11 | 4a8355280594 |
12 | 1ab3017252a7 |
13 | a3c099c4314 |
14 | 4ca4da89075 |
15 | 26e24763e4d |
hex | 14aac8fe95f |
1420234320223 has 2 divisors, whose sum is σ = 1420234320224. Its totient is φ = 1420234320222.
The previous prime is 1420234320133. The next prime is 1420234320257. The reversal of 1420234320223 is 3220234320241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1420234320223 - 213 = 1420234312031 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1420234320191 and 1420234320200.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1420234320023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710117160111 + 710117160112.
It is an arithmetic number, because the mean of its divisors is an integer number (710117160112).
Almost surely, 21420234320223 is an apocalyptic number.
1420234320223 is a deficient number, since it is larger than the sum of its proper divisors (1).
1420234320223 is an equidigital number, since it uses as much as digits as its factorization.
1420234320223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 28.
Adding to 1420234320223 its reverse (3220234320241), we get a palindrome (4640468640464).
The spelling of 1420234320223 in words is "one trillion, four hundred twenty billion, two hundred thirty-four million, three hundred twenty thousand, two hundred twenty-three".
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