Base | Representation |
---|---|
bin | 10100101010101101101… |
… | …011101111000110001011 |
3 | 12000202220212211110101021 |
4 | 110222231223233012023 |
5 | 141232134300144042 |
6 | 3004242201333311 |
7 | 204416124266434 |
oct | 24525553570613 |
9 | 5022825743337 |
10 | 1420253131147 |
11 | 4a8364959504 |
12 | 1ab307a97237 |
13 | a3c1087c446 |
14 | 4ca5238448b |
15 | 26e2622c867 |
hex | 14aadaef18b |
1420253131147 has 2 divisors, whose sum is σ = 1420253131148. Its totient is φ = 1420253131146.
The previous prime is 1420253131139. The next prime is 1420253131159. The reversal of 1420253131147 is 7411313520241.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1420253131147 - 23 = 1420253131139 is a prime.
It is not a weakly prime, because it can be changed into another prime (1420253134147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710126565573 + 710126565574.
It is an arithmetic number, because the mean of its divisors is an integer number (710126565574).
Almost surely, 21420253131147 is an apocalyptic number.
1420253131147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1420253131147 is an equidigital number, since it uses as much as digits as its factorization.
1420253131147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20160, while the sum is 34.
Adding to 1420253131147 its reverse (7411313520241), we get a palindrome (8831566651388).
The spelling of 1420253131147 in words is "one trillion, four hundred twenty billion, two hundred fifty-three million, one hundred thirty-one thousand, one hundred forty-seven".
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