Base | Representation |
---|---|
bin | 100000010010110011110110… |
… | …011111101001001010100111 |
3 | 200121212221112211221211122120 |
4 | 200102303312133221022213 |
5 | 122104010133143044333 |
6 | 1222023422244201023 |
7 | 41626223425616463 |
oct | 4022636637511247 |
9 | 617787484854576 |
10 | 142030114034343 |
11 | 412896a6722817 |
12 | 13b1a479999173 |
13 | 61334c7b555b2 |
14 | 27104193cb4a3 |
15 | 11647e111adb3 |
hex | 812cf67e92a7 |
142030114034343 has 32 divisors (see below), whose sum is σ = 196346785615872. Its totient is φ = 91227930393600.
The previous prime is 142030114034329. The next prime is 142030114034363. The reversal of 142030114034343 is 343430411030241.
It is not a de Polignac number, because 142030114034343 - 212 = 142030114030247 is a prime.
It is a super-2 number, since 2×1420301140343432 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (142030114034363) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 17286921 + ... + 24143277.
It is an arithmetic number, because the mean of its divisors is an integer number (6135837050496).
Almost surely, 2142030114034343 is an apocalyptic number.
142030114034343 is a deficient number, since it is larger than the sum of its proper divisors (54316671581529).
142030114034343 is a wasteful number, since it uses less digits than its factorization.
142030114034343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6857375.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 142030114034343 its reverse (343430411030241), we get a palindrome (485460525064584).
The spelling of 142030114034343 in words is "one hundred forty-two trillion, thirty billion, one hundred fourteen million, thirty-four thousand, three hundred forty-three".
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