14203101433123 has 2 divisors, whose sum is σ = 14203101433124. Its totient is φ = 14203101433122.

The previous prime is 14203101433121. The next prime is 14203101433231. The reversal of 14203101433123 is 32133410130241.

Together with next prime (14203101433231) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14203101433123 - 2¹ = 14203101433121 is a prime.

Together with 14203101433121, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 14203101433091 and 14203101433100.

It is not a weakly prime, because it can be changed into another prime (14203101433121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7101550716561 + 7101550716562.

It is an arithmetic number, because the mean of its divisors is an integer number (7101550716562).

Almost surely, 2^{14203101433123} is an apocalyptic number.

14203101433123 is a deficient number, since it is larger than the sum of its proper divisors (1).

14203101433123 is an equidigital number, since it uses as much as digits as its factorization.

14203101433123 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 14203101433123 its reverse (32133410130241), we get a palindrome (46336511563364).

The spelling of 14203101433123 in words is "fourteen trillion, two hundred three billion, one hundred one million, four hundred thirty-three thousand, one hundred twenty-three".