Base | Representation |
---|---|
bin | 10100101010110001111… |
… | …100101000001001111111 |
3 | 12000210002212102220112111 |
4 | 110222301330220021333 |
5 | 141232311103334111 |
6 | 3004253234514451 |
7 | 204420653323663 |
oct | 24526174501177 |
9 | 5023085386474 |
10 | 1420324668031 |
11 | 4a83a127a1a5 |
12 | 1ab327a35a27 |
13 | a3c22638669 |
14 | 4ca5ba868a3 |
15 | 26e2c65da21 |
hex | 14ab1f2827f |
1420324668031 has 2 divisors, whose sum is σ = 1420324668032. Its totient is φ = 1420324668030.
The previous prime is 1420324668013. The next prime is 1420324668053. The reversal of 1420324668031 is 1308664230241.
Together with previous prime (1420324668013) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1420324668031 - 25 = 1420324667999 is a prime.
It is a super-2 number, since 2×14203246680312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1420324668131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710162334015 + 710162334016.
It is an arithmetic number, because the mean of its divisors is an integer number (710162334016).
Almost surely, 21420324668031 is an apocalyptic number.
1420324668031 is a deficient number, since it is larger than the sum of its proper divisors (1).
1420324668031 is an equidigital number, since it uses as much as digits as its factorization.
1420324668031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 165888, while the sum is 40.
Adding to 1420324668031 its reverse (1308664230241), we get a palindrome (2728988898272).
The spelling of 1420324668031 in words is "one trillion, four hundred twenty billion, three hundred twenty-four million, six hundred sixty-eight thousand, thirty-one".
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