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14204054321 is a prime number
BaseRepresentation
bin11010011101010000…
…01010101100110001
31100122220102201110222
431032220022230301
5213042214214241
610305242102425
71011663320042
oct151650125461
940586381428
1014204054321
116029900276
122904aaaa15
131454985692
1498a6328c9
15581edda4b
hex34ea0ab31

14204054321 has 2 divisors, whose sum is σ = 14204054322. Its totient is φ = 14204054320.

The previous prime is 14204054311. The next prime is 14204054383. The reversal of 14204054321 is 12345040241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9132478096 + 5071576225 = 95564^2 + 71215^2 .

It is an emirp because it is prime and its reverse (12345040241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14204054321 - 214 = 14204037937 is a prime.

It is not a weakly prime, because it can be changed into another prime (14204054311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7102027160 + 7102027161.

It is an arithmetic number, because the mean of its divisors is an integer number (7102027161).

Almost surely, 214204054321 is an apocalyptic number.

It is an amenable number.

14204054321 is a deficient number, since it is larger than the sum of its proper divisors (1).

14204054321 is an equidigital number, since it uses as much as digits as its factorization.

14204054321 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3840, while the sum is 26.

Adding to 14204054321 its reverse (12345040241), we get a palindrome (26549094562).

The spelling of 14204054321 in words is "fourteen billion, two hundred four million, fifty-four thousand, three hundred twenty-one".