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12345040241 is a prime number
BaseRepresentation
bin10110111111101001…
…00101110101110001
31011212100101000120122
423133310211311301
5200240312241431
65400553020025
7614631052652
oct133764456561
934770330518
1012345040241
1152654a94a6
1224863b4615
1312197a2351
14851797529
154c3bc9a7b
hex2dfd25d71

12345040241 has 2 divisors, whose sum is σ = 12345040242. Its totient is φ = 12345040240.

The previous prime is 12345040139. The next prime is 12345040243. The reversal of 12345040241 is 14204054321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10220199025 + 2124841216 = 101095^2 + 46096^2 .

It is an emirp because it is prime and its reverse (14204054321) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12345040241 - 214 = 12345023857 is a prime.

It is a Sophie Germain prime.

Together with 12345040243, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 12345040241.

It is not a weakly prime, because it can be changed into another prime (12345040243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6172520120 + 6172520121.

It is an arithmetic number, because the mean of its divisors is an integer number (6172520121).

Almost surely, 212345040241 is an apocalyptic number.

It is an amenable number.

12345040241 is a deficient number, since it is larger than the sum of its proper divisors (1).

12345040241 is an equidigital number, since it uses as much as digits as its factorization.

12345040241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3840, while the sum is 26.

Adding to 12345040241 its reverse (14204054321), we get a palindrome (26549094562).

The spelling of 12345040241 in words is "twelve billion, three hundred forty-five million, forty thousand, two hundred forty-one".