14204140134533 has 2 divisors, whose sum is σ = 14204140134534. Its totient is φ = 14204140134532.

The previous prime is 14204140134497. The next prime is 14204140134539. The reversal of 14204140134533 is 33543104140241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13240850884804 + 963289249729 = 3638798^2 + 981473^2 .

It is an emirp because it is prime and its reverse (33543104140241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14204140134533 - 2⁶ = 14204140134469 is a prime.

It is a super-2 number, since 2×14204140134533² (a number of 27 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 14204140134493 and 14204140134502.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14204140134539) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7102070067266 + 7102070067267.

It is an arithmetic number, because the mean of its divisors is an integer number (7102070067267).

Almost surely, 2^{14204140134533} is an apocalyptic number.

It is an amenable number.

14204140134533 is a deficient number, since it is larger than the sum of its proper divisors (1).

14204140134533 is an equidigital number, since it uses as much as digits as its factorization.

14204140134533 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 69120, while the sum is 35.

Adding to 14204140134533 its reverse (33543104140241), we get a palindrome (47747244274774).

The spelling of 14204140134533 in words is "fourteen trillion, two hundred four billion, one hundred forty million, one hundred thirty-four thousand, five hundred thirty-three".