Base | Representation |
---|---|
bin | 11010011101010011… |
… | …01001110110010101 |
3 | 1100122221011112002111 |
4 | 31032221221312111 |
5 | 213042314202203 |
6 | 10305254311021 |
7 | 1011666532222 |
oct | 151651516625 |
9 | 40587145074 |
10 | 14204444053 |
11 | 602a047068 |
12 | 2905058471 |
13 | 1454a90ba7 |
14 | 98a6d4949 |
15 | 58206926d |
hex | 34ea69d95 |
14204444053 has 2 divisors, whose sum is σ = 14204444054. Its totient is φ = 14204444052.
The previous prime is 14204444021. The next prime is 14204444071. The reversal of 14204444053 is 35044440241.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12585025489 + 1619418564 = 112183^2 + 40242^2 .
It is a cyclic number.
It is not a de Polignac number, because 14204444053 - 25 = 14204444021 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14204444083) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7102222026 + 7102222027.
It is an arithmetic number, because the mean of its divisors is an integer number (7102222027).
Almost surely, 214204444053 is an apocalyptic number.
It is an amenable number.
14204444053 is a deficient number, since it is larger than the sum of its proper divisors (1).
14204444053 is an equidigital number, since it uses as much as digits as its factorization.
14204444053 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 30720, while the sum is 31.
Adding to 14204444053 its reverse (35044440241), we get a palindrome (49248884294).
The spelling of 14204444053 in words is "fourteen billion, two hundred four million, four hundred forty-four thousand, fifty-three".
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