142051131041 has 2 divisors, whose sum is σ = 142051131042. Its totient is φ = 142051131040.

The previous prime is 142051131031. The next prime is 142051131043. The reversal of 142051131041 is 140131150241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 141868989025 + 182142016 = 376655^2 + 13496^2 .

It is a cyclic number.

It is not a de Polignac number, because 142051131041 - 2²⁶ = 141984022177 is a prime.

Together with 142051131043, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 142051130998 and 142051131016.

It is not a weakly prime, because it can be changed into another prime (142051131043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71025565520 + 71025565521.

It is an arithmetic number, because the mean of its divisors is an integer number (71025565521).

Almost surely, 2^142051131041 is an apocalyptic number.

It is an amenable number.

142051131041 is a deficient number, since it is larger than the sum of its proper divisors (1).

142051131041 is an equidigital number, since it uses as much as digits as its factorization.

142051131041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 480, while the sum is 23.

Adding to 142051131041 its reverse (140131150241), we get a palindrome (282182281282).

The spelling of 142051131041 in words is "one hundred forty-two billion, fifty-one million, one hundred thirty-one thousand, forty-one".