Base | Representation |
---|---|
bin | 11010011101011011… |
… | …10001110110001111 |
3 | 1100200000012110102001 |
4 | 31032231301312033 |
5 | 213043103303031 |
6 | 10305333413131 |
7 | 1012011654631 |
oct | 151655616617 |
9 | 40600173361 |
10 | 14205525391 |
11 | 602a715532 |
12 | 290549a1a7 |
13 | 145507c135 |
14 | 98a8d6a51 |
15 | 5821ce861 |
hex | 34eb71d8f |
14205525391 has 2 divisors, whose sum is σ = 14205525392. Its totient is φ = 14205525390.
The previous prime is 14205525371. The next prime is 14205525401. The reversal of 14205525391 is 19352550241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14205525391 - 217 = 14205394319 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 14205525391.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14205525331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7102762695 + 7102762696.
It is an arithmetic number, because the mean of its divisors is an integer number (7102762696).
Almost surely, 214205525391 is an apocalyptic number.
14205525391 is a deficient number, since it is larger than the sum of its proper divisors (1).
14205525391 is an equidigital number, since it uses as much as digits as its factorization.
14205525391 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54000, while the sum is 37.
The spelling of 14205525391 in words is "fourteen billion, two hundred five million, five hundred twenty-five thousand, three hundred ninety-one".
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