Base | Representation |
---|---|
bin | 1100111010110111101101… |
… | …0011011011111001000101 |
3 | 1212022000221111111011202011 |
4 | 3032231323103123321011 |
5 | 3330220404014243141 |
6 | 50113532304414221 |
7 | 2664213110541625 |
oct | 316557323337105 |
9 | 55260844434664 |
10 | 14205525540421 |
11 | 4587590915116 |
12 | 1715161917371 |
13 | 7c0762c59c67 |
14 | 3717a0334885 |
15 | 1997b94d9881 |
hex | ceb7b4dbe45 |
14205525540421 has 2 divisors, whose sum is σ = 14205525540422. Its totient is φ = 14205525540420.
The previous prime is 14205525540403. The next prime is 14205525540431. The reversal of 14205525540421 is 12404552550241.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11158706416225 + 3046819124196 = 3340465^2 + 1745514^2 .
It is a cyclic number.
It is not a de Polignac number, because 14205525540421 - 25 = 14205525540389 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14205525540431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7102762770210 + 7102762770211.
It is an arithmetic number, because the mean of its divisors is an integer number (7102762770211).
Almost surely, 214205525540421 is an apocalyptic number.
It is an amenable number.
14205525540421 is a deficient number, since it is larger than the sum of its proper divisors (1).
14205525540421 is an equidigital number, since it uses as much as digits as its factorization.
14205525540421 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 320000, while the sum is 40.
The spelling of 14205525540421 in words is "fourteen trillion, two hundred five billion, five hundred twenty-five million, five hundred forty thousand, four hundred twenty-one".
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