14210035607 has 2 divisors, whose sum is σ = 14210035608. Its totient is φ = 14210035606.

The previous prime is 14210035603. The next prime is 14210035639. The reversal of 14210035607 is 70653001241.

It is a weak prime.

It is an emirp because it is prime and its reverse (70653001241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14210035607 - 2² = 14210035603 is a prime.

It is a super-2 number, since 2×14210035607² (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 14210035607.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14210035603) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7105017803 + 7105017804.

It is an arithmetic number, because the mean of its divisors is an integer number (7105017804).

Almost surely, 2^14210035607 is an apocalyptic number.

14210035607 is a deficient number, since it is larger than the sum of its proper divisors (1).

14210035607 is an equidigital number, since it uses as much as digits as its factorization.

14210035607 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5040, while the sum is 29.

Adding to 14210035607 its reverse (70653001241), we get a palindrome (84863036848).

The spelling of 14210035607 in words is "fourteen billion, two hundred ten million, thirty-five thousand, six hundred seven".