14210665220137 has 2 divisors, whose sum is σ = 14210665220138. Its totient is φ = 14210665220136.

The previous prime is 14210665220131. The next prime is 14210665220201. The reversal of 14210665220137 is 73102256601241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13648916469136 + 561748751001 = 3694444^2 + 749499^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14210665220137 is a prime.

It is a super-3 number, since 3×14210665220137³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 14210665220137.

It is not a weakly prime, because it can be changed into another prime (14210665220131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7105332610068 + 7105332610069.

It is an arithmetic number, because the mean of its divisors is an integer number (7105332610069).

Almost surely, 2^{14210665220137} is an apocalyptic number.

It is an amenable number.

14210665220137 is a deficient number, since it is larger than the sum of its proper divisors (1).

14210665220137 is an equidigital number, since it uses as much as digits as its factorization.

14210665220137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120960, while the sum is 40.

The spelling of 14210665220137 in words is "fourteen trillion, two hundred ten billion, six hundred sixty-five million, two hundred twenty thousand, one hundred thirty-seven".