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14210665220131 is a prime number
BaseRepresentation
bin1100111011001010110110…
…1001110000100000100011
31212022112012200200221211221
43032302231221300200203
53330311420244021011
650120142305515511
72664454350233602
oct316625551604043
955275180627757
1014210665220131
1145897890555a6
121716157042b97
137c10a1a13163
14371b2ab95a39
151999ba832971
hexcecada70823

14210665220131 has 2 divisors, whose sum is σ = 14210665220132. Its totient is φ = 14210665220130.

The previous prime is 14210665220093. The next prime is 14210665220137. The reversal of 14210665220131 is 13102256601241.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14210665220131 is a prime.

It is a super-3 number, since 3×142106652201313 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (14210665220137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7105332610065 + 7105332610066.

It is an arithmetic number, because the mean of its divisors is an integer number (7105332610066).

Almost surely, 214210665220131 is an apocalyptic number.

14210665220131 is a deficient number, since it is larger than the sum of its proper divisors (1).

14210665220131 is an equidigital number, since it uses as much as digits as its factorization.

14210665220131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17280, while the sum is 34.

The spelling of 14210665220131 in words is "fourteen trillion, two hundred ten billion, six hundred sixty-five million, two hundred twenty thousand, one hundred thirty-one".