Base | Representation |
---|---|
bin | 1100111011001010110110… |
… | …1001110000100000100011 |
3 | 1212022112012200200221211221 |
4 | 3032302231221300200203 |
5 | 3330311420244021011 |
6 | 50120142305515511 |
7 | 2664454350233602 |
oct | 316625551604043 |
9 | 55275180627757 |
10 | 14210665220131 |
11 | 45897890555a6 |
12 | 1716157042b97 |
13 | 7c10a1a13163 |
14 | 371b2ab95a39 |
15 | 1999ba832971 |
hex | cecada70823 |
14210665220131 has 2 divisors, whose sum is σ = 14210665220132. Its totient is φ = 14210665220130.
The previous prime is 14210665220093. The next prime is 14210665220137. The reversal of 14210665220131 is 13102256601241.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14210665220131 is a prime.
It is a super-3 number, since 3×142106652201313 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (14210665220137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7105332610065 + 7105332610066.
It is an arithmetic number, because the mean of its divisors is an integer number (7105332610066).
Almost surely, 214210665220131 is an apocalyptic number.
14210665220131 is a deficient number, since it is larger than the sum of its proper divisors (1).
14210665220131 is an equidigital number, since it uses as much as digits as its factorization.
14210665220131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17280, while the sum is 34.
The spelling of 14210665220131 in words is "fourteen trillion, two hundred ten billion, six hundred sixty-five million, two hundred twenty thousand, one hundred thirty-one".
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