Base | Representation |
---|---|
bin | 100000010100000000010011… |
… | …110100011110001100110111 |
3 | 200122011210110021202221122011 |
4 | 200110000103310132030313 |
5 | 122111331301331143333 |
6 | 1222125240450345051 |
7 | 41635161024411343 |
oct | 4024002364361467 |
9 | 618153407687564 |
10 | 142112210412343 |
11 | 413104a4a136a6 |
12 | 13b3236b88b187 |
13 | 613b17c3aa762 |
14 | 27143a674c623 |
15 | 11669e86889cd |
hex | 814013d1e337 |
142112210412343 has 2 divisors, whose sum is σ = 142112210412344. Its totient is φ = 142112210412342.
The previous prime is 142112210412331. The next prime is 142112210412407. The reversal of 142112210412343 is 343214012211241.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 142112210412343 - 217 = 142112210281271 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (142112210412043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71056105206171 + 71056105206172.
It is an arithmetic number, because the mean of its divisors is an integer number (71056105206172).
Almost surely, 2142112210412343 is an apocalyptic number.
142112210412343 is a deficient number, since it is larger than the sum of its proper divisors (1).
142112210412343 is an equidigital number, since it uses as much as digits as its factorization.
142112210412343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9216, while the sum is 31.
Adding to 142112210412343 its reverse (343214012211241), we get a palindrome (485326222623584).
The spelling of 142112210412343 in words is "one hundred forty-two trillion, one hundred twelve billion, two hundred ten million, four hundred twelve thousand, three hundred forty-three".
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