142112220044130 has 128 divisors (see below), whose sum is σ = 433231649832960. Its totient is φ = 32473212569280.

The previous prime is 142112220044107. The next prime is 142112220044153. The reversal of 142112220044130 is 31440022211241.

142112220044130 is a `hidden beast` number, since 1 + 4 + 2 + 1 + 12 + 2 + 200 + 441 + 3 + 0 = 666.

It is an interprime number because it is at equal distance from previous prime (142112220044107) and next prime (142112220044153).

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 142112220044094 and 142112220044103.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 4677954 + ... + 17495933.

It is an arithmetic number, because the mean of its divisors is an integer number (3384622264320).

Almost surely, 2^{142112220044130} is an apocalyptic number.

142112220044130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

142112220044130 is an abundant number, since it is smaller than the sum of its proper divisors (291119429788830).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

142112220044130 is a wasteful number, since it uses less digits than its factorization.

142112220044130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22177301 (or 22177295 counting only the distinct ones).

The product of its (nonzero) digits is 3072, while the sum is 27.

Adding to 142112220044130 its reverse (31440022211241), we get a palindrome (173552242255371).

The spelling of 142112220044130 in words is "one hundred forty-two trillion, one hundred twelve billion, two hundred twenty million, forty-four thousand, one hundred thirty".