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14211565502081 is a prime number
BaseRepresentation
bin1100111011001110001101…
…0100000011111010000001
31212022121112102202000111212
43032303203110003322001
53330320241232031311
650120411510015505
72664515561425403
oct316634324037201
955277472660455
1014211565502081
11458a10025a772
121716368647595
137c11b63a7c7c
14371bb4586b73
15199a1e8b7c8b
hexcece3503e81

14211565502081 has 2 divisors, whose sum is σ = 14211565502082. Its totient is φ = 14211565502080.

The previous prime is 14211565502039. The next prime is 14211565502177. The reversal of 14211565502081 is 18020556511241.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13237809024400 + 973756477681 = 3638380^2 + 986791^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14211565502081 is a prime.

It is a super-2 number, since 2×142115655020812 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14211565502881) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7105782751040 + 7105782751041.

It is an arithmetic number, because the mean of its divisors is an integer number (7105782751041).

Almost surely, 214211565502081 is an apocalyptic number.

It is an amenable number.

14211565502081 is a deficient number, since it is larger than the sum of its proper divisors (1).

14211565502081 is an equidigital number, since it uses as much as digits as its factorization.

14211565502081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96000, while the sum is 41.

The spelling of 14211565502081 in words is "fourteen trillion, two hundred eleven billion, five hundred sixty-five million, five hundred two thousand, eighty-one".