Base | Representation |
---|---|
bin | 11010011110001101… |
… | …00001110101111101 |
3 | 1100200110102002100001 |
4 | 31033012201311331 |
5 | 213101233412222 |
6 | 10310124434301 |
7 | 1012121056336 |
oct | 151706416575 |
9 | 40613362301 |
10 | 14212013437 |
11 | 6033347056 |
12 | 29076a8991 |
13 | 145651130b |
14 | 98b70528d |
15 | 582a61e27 |
hex | 34f1a1d7d |
14212013437 has 2 divisors, whose sum is σ = 14212013438. Its totient is φ = 14212013436.
The previous prime is 14212013419. The next prime is 14212013443. The reversal of 14212013437 is 73431021241.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12925643481 + 1286369956 = 113691^2 + 35866^2 .
It is a cyclic number.
It is not a de Polignac number, because 14212013437 - 211 = 14212011389 is a prime.
It is a super-3 number, since 3×142120134373 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14212013407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106006718 + 7106006719.
It is an arithmetic number, because the mean of its divisors is an integer number (7106006719).
Almost surely, 214212013437 is an apocalyptic number.
It is an amenable number.
14212013437 is a deficient number, since it is larger than the sum of its proper divisors (1).
14212013437 is an equidigital number, since it uses as much as digits as its factorization.
14212013437 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 28.
Adding to 14212013437 its reverse (73431021241), we get a palindrome (87643034678).
The spelling of 14212013437 in words is "fourteen billion, two hundred twelve million, thirteen thousand, four hundred thirty-seven".
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