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14212242411151 is a prime number
BaseRepresentation
bin1100111011010000101110…
…1010010000111010001111
31212022200021121110120012011
43032310023222100322033
53330323133024124101
650121003010322051
72664541421155261
oct316641352207217
955280247416164
1014212242411151
11458a418368554
121716517289327
137c12936c1095
14371c3a42db31
15199a5e028751
hexced0ba90e8f

14212242411151 has 2 divisors, whose sum is σ = 14212242411152. Its totient is φ = 14212242411150.

The previous prime is 14212242411089. The next prime is 14212242411173. The reversal of 14212242411151 is 15111424221241.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14212242411151 - 213 = 14212242402959 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14212242411751) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106121205575 + 7106121205576.

It is an arithmetic number, because the mean of its divisors is an integer number (7106121205576).

Almost surely, 214212242411151 is an apocalyptic number.

14212242411151 is a deficient number, since it is larger than the sum of its proper divisors (1).

14212242411151 is an equidigital number, since it uses as much as digits as its factorization.

14212242411151 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5120, while the sum is 31.

Adding to 14212242411151 its reverse (15111424221241), we get a palindrome (29323666632392).

The spelling of 14212242411151 in words is "fourteen trillion, two hundred twelve billion, two hundred forty-two million, four hundred eleven thousand, one hundred fifty-one".