Base | Representation |
---|---|
bin | 1100111011010001011001… |
… | …1000010000011100011111 |
3 | 1212022200202010211211001001 |
4 | 3032310112120100130133 |
5 | 3330324020043140111 |
6 | 50121032512531131 |
7 | 2664546033531601 |
oct | 316642630203437 |
9 | 55280663754031 |
10 | 14212422240031 |
11 | 458a4aa923664 |
12 | 1716567550aa7 |
13 | 7c12c1a350c2 |
14 | 371c56281171 |
15 | 199a6ebeb1c1 |
hex | ced1661071f |
14212422240031 has 2 divisors, whose sum is σ = 14212422240032. Its totient is φ = 14212422240030.
The previous prime is 14212422239969. The next prime is 14212422240053. The reversal of 14212422240031 is 13004222421241.
14212422240031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14212422240031 - 211 = 14212422237983 is a prime.
It is a super-2 number, since 2×142124222400312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14212422240091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106211120015 + 7106211120016.
It is an arithmetic number, because the mean of its divisors is an integer number (7106211120016).
Almost surely, 214212422240031 is an apocalyptic number.
14212422240031 is a deficient number, since it is larger than the sum of its proper divisors (1).
14212422240031 is an equidigital number, since it uses as much as digits as its factorization.
14212422240031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6144, while the sum is 28.
Adding to 14212422240031 its reverse (13004222421241), we get a palindrome (27216644661272).
The spelling of 14212422240031 in words is "fourteen trillion, two hundred twelve billion, four hundred twenty-two million, two hundred forty thousand, thirty-one".
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