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14212440413 is a prime number
BaseRepresentation
bin11010011110010000…
…01010000101011101
31100200111012210000222
431033020022011131
5213101341043123
610310141531125
71012124515223
oct151710120535
940614183028
1014212440413
116033608926
122907873aa5
131456630772
1498b7b6b13
15582ae86c8
hex34f20a15d

14212440413 has 2 divisors, whose sum is σ = 14212440414. Its totient is φ = 14212440412.

The previous prime is 14212440383. The next prime is 14212440433. The reversal of 14212440413 is 31404421241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9484227769 + 4728212644 = 97387^2 + 68762^2 .

It is a cyclic number.

It is not a de Polignac number, because 14212440413 - 28 = 14212440157 is a prime.

It is a super-2 number, since 2×142124404132 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14212440433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106220206 + 7106220207.

It is an arithmetic number, because the mean of its divisors is an integer number (7106220207).

Almost surely, 214212440413 is an apocalyptic number.

It is an amenable number.

14212440413 is a deficient number, since it is larger than the sum of its proper divisors (1).

14212440413 is an equidigital number, since it uses as much as digits as its factorization.

14212440413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3072, while the sum is 26.

Adding to 14212440413 its reverse (31404421241), we get a palindrome (45616861654).

The spelling of 14212440413 in words is "fourteen billion, two hundred twelve million, four hundred forty thousand, four hundred thirteen".