Base | Representation |
---|---|
bin | 1000010001011101010… |
… | …1010111111111011111 |
3 | 111120211222000101110212 |
4 | 2010113111113333133 |
5 | 4312033100300111 |
6 | 145142544323035 |
7 | 13160666652566 |
oct | 2042725277737 |
9 | 446758011425 |
10 | 142125400031 |
11 | 553030a069a |
12 | 2366561347b |
13 | 10530004154 |
14 | 6c43a0abdd |
15 | 3a6c60498b |
hex | 2117557fdf |
142125400031 has 2 divisors, whose sum is σ = 142125400032. Its totient is φ = 142125400030.
The previous prime is 142125400019. The next prime is 142125400049. The reversal of 142125400031 is 130004521241.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 142125400031 - 210 = 142125399007 is a prime.
It is a super-2 number, since 2×1421254000312 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (142125400531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71062700015 + 71062700016.
It is an arithmetic number, because the mean of its divisors is an integer number (71062700016).
Almost surely, 2142125400031 is an apocalyptic number.
142125400031 is a deficient number, since it is larger than the sum of its proper divisors (1).
142125400031 is an equidigital number, since it uses as much as digits as its factorization.
142125400031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 960, while the sum is 23.
Adding to 142125400031 its reverse (130004521241), we get a palindrome (272129921272).
The spelling of 142125400031 in words is "one hundred forty-two billion, one hundred twenty-five million, four hundred thousand, thirty-one".
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