14213033340001 has 2 divisors, whose sum is σ = 14213033340002. Its totient is φ = 14213033340000.

The previous prime is 14213033339987. The next prime is 14213033340047. The reversal of 14213033340001 is 10004333031241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9569865990400 + 4643167349601 = 3093520^2 + 2154801^2 .

It is a cyclic number.

It is not a de Polignac number, because 14213033340001 - 2¹¹ = 14213033337953 is a prime.

It is not a weakly prime, because it can be changed into another prime (14213033340301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106516670000 + 7106516670001.

It is an arithmetic number, because the mean of its divisors is an integer number (7106516670001).

Almost surely, 2^{14213033340001} is an apocalyptic number.

It is an amenable number.

14213033340001 is a deficient number, since it is larger than the sum of its proper divisors (1).

14213033340001 is an equidigital number, since it uses as much as digits as its factorization.

14213033340001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 14213033340001 its reverse (10004333031241), we get a palindrome (24217366371242).

The spelling of 14213033340001 in words is "fourteen trillion, two hundred thirteen billion, thirty-three million, three hundred forty thousand, one".