Base | Representation |
---|---|
bin | 10100101011101100101… |
… | …100100101110111111101 |
3 | 12000212122120010020000121 |
4 | 110223230230211313331 |
5 | 141241320420221000 |
6 | 3004535124454541 |
7 | 204454252246153 |
oct | 24535454456775 |
9 | 5025576106017 |
10 | 1421310320125 |
11 | 4a8857693203 |
12 | 1ab561b4a451 |
13 | a404b8c0c57 |
14 | 4cb1293b3d3 |
15 | 26e88e58b1a |
hex | 14aecb25dfd |
1421310320125 has 64 divisors (see below), whose sum is σ = 1917948764160. Its totient is φ = 1048863816000.
The previous prime is 1421310320117. The next prime is 1421310320153. The reversal of 1421310320125 is 5210230131241.
It is not a de Polignac number, because 1421310320125 - 23 = 1421310320117 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is a self number, because there is not a number n which added to its sum of digits gives 1421310320125.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 9693610 + ... + 9839140.
It is an arithmetic number, because the mean of its divisors is an integer number (29967949440).
Almost surely, 21421310320125 is an apocalyptic number.
It is an amenable number.
1421310320125 is a deficient number, since it is larger than the sum of its proper divisors (496638444035).
1421310320125 is a wasteful number, since it uses less digits than its factorization.
1421310320125 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 145691 (or 145681 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 1421310320125 its reverse (5210230131241), we get a palindrome (6631540451366).
The spelling of 1421310320125 in words is "one trillion, four hundred twenty-one billion, three hundred ten million, three hundred twenty thousand, one hundred twenty-five".
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