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14213110232401 is a prime number
BaseRepresentation
bin1100111011010011111101…
…1000101111010101010001
31212022202112002102110010221
43032310333120233111101
53330331422204414101
650121225050553041
72664602056422343
oct316647730572521
955282462373127
1014213110232401
11458a8232114a3
121716719a38781
137c13a142bb92
14371cbd7b1293
15199ab02eaaa1
hexced3f62f551

14213110232401 has 2 divisors, whose sum is σ = 14213110232402. Its totient is φ = 14213110232400.

The previous prime is 14213110232351. The next prime is 14213110232417. The reversal of 14213110232401 is 10423201131241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10125633126400 + 4087477106001 = 3182080^2 + 2021751^2 .

It is an emirp because it is prime and its reverse (10423201131241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14213110232401 - 27 = 14213110232273 is a prime.

It is not a weakly prime, because it can be changed into another prime (14213110232441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106555116200 + 7106555116201.

It is an arithmetic number, because the mean of its divisors is an integer number (7106555116201).

Almost surely, 214213110232401 is an apocalyptic number.

It is an amenable number.

14213110232401 is a deficient number, since it is larger than the sum of its proper divisors (1).

14213110232401 is an equidigital number, since it uses as much as digits as its factorization.

14213110232401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 14213110232401 its reverse (10423201131241), we get a palindrome (24636311363642).

The spelling of 14213110232401 in words is "fourteen trillion, two hundred thirteen billion, one hundred ten million, two hundred thirty-two thousand, four hundred one".