Search a number
-
+
1421311300 = 225214213113
BaseRepresentation
bin101010010110111…
…0111110101000100
310200001110002120021
41110231313311010
510402323430200
6353011344524
750135642503
oct12455676504
93601402507
101421311300
1166a325242
12337bb2144
13198600a06
14d6a9c83a
1584ba441a
hex54b77d44

1421311300 has 18 divisors (see below), whose sum is σ = 3084245738. Its totient is φ = 568524480.

The previous prime is 1421311273. The next prime is 1421311319. The reversal of 1421311300 is 31131241.

It can be written as a sum of positive squares in 3 ways, for example, as 1679616 + 1419631684 = 1296^2 + 37678^2 .

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 7106457 + ... + 7106656.

Almost surely, 21421311300 is an apocalyptic number.

1421311300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1421311300 is an abundant number, since it is smaller than the sum of its proper divisors (1662934438).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1421311300 is a wasteful number, since it uses less digits than its factorization.

1421311300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14213127 (or 14213120 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 1421311300 is about 37700.2824923103. The cubic root of 1421311300 is about 1124.3367415545.

Adding to 1421311300 its reverse (31131241), we get a palindrome (1452442541).

The spelling of 1421311300 in words is "one billion, four hundred twenty-one million, three hundred eleven thousand, three hundred".

Divisors: 1 2 4 5 10 20 25 50 100 14213113 28426226 56852452 71065565 142131130 284262260 355327825 710655650 1421311300