Base | Representation |
---|---|
bin | 100000010100010010000000… |
… | …011110110000000101000010 |
3 | 200122020121111122001212120002 |
4 | 200110102000132300011002 |
5 | 122112134211101213010 |
6 | 1222142102240320002 |
7 | 41636432651340251 |
oct | 4024220036600502 |
9 | 618217448055502 |
10 | 142131213304130 |
11 | 41318566614546 |
12 | 13b35b93913002 |
13 | 613cbba31b51b |
14 | 271528a43a798 |
15 | 116725bae51a5 |
hex | 8144807b0142 |
142131213304130 has 32 divisors (see below), whose sum is σ = 255884487595776. Its totient is φ = 56841752179584.
The previous prime is 142131213304079. The next prime is 142131213304141. The reversal of 142131213304130 is 31403312131241.
It is a junction number, because it is equal to n+sod(n) for n = 142131213304093 and 142131213304102.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1424296097 + ... + 1424395883.
It is an arithmetic number, because the mean of its divisors is an integer number (7996390237368).
Almost surely, 2142131213304130 is an apocalyptic number.
142131213304130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
142131213304130 is a deficient number, since it is larger than the sum of its proper divisors (113753274291646).
142131213304130 is a wasteful number, since it uses less digits than its factorization.
142131213304130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 125258.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 142131213304130 its reverse (31403312131241), we get a palindrome (173534525435371).
The spelling of 142131213304130 in words is "one hundred forty-two trillion, one hundred thirty-one billion, two hundred thirteen million, three hundred four thousand, one hundred thirty".
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