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14213121411130 = 254415693218777
BaseRepresentation
bin1100111011010100000000…
…0011011000100000111010
31212022202112212110101110221
43032311000003120200322
53330331433040124010
650121230130330254
72664602253431365
oct316650003304072
955282485411427
1014213121411130
11458a829557214
12171672172998a
137c13a3844105
14371cc10810dc
15199ab12a7dda
hexced400d883a

14213121411130 has 16 divisors (see below), whose sum is σ = 25583684426280. Its totient is φ = 5685233923072.

The previous prime is 14213121411113. The next prime is 14213121411211. The reversal of 14213121411130 is 3111412131241.

It can be written as a sum of positive squares in 4 ways, for example, as 14111945888569 + 101175522561 = 3756587^2 + 318081^2 .

It is a junction number, because it is equal to n+sod(n) for n = 14213121411095 and 14213121411104.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2806302 + ... + 6025078.

Almost surely, 214213121411130 is an apocalyptic number.

14213121411130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

14213121411130 is a deficient number, since it is larger than the sum of its proper divisors (11370563015150).

14213121411130 is a wasteful number, since it uses less digits than its factorization.

14213121411130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3660353.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 14213121411130 its reverse (3111412131241), we get a palindrome (17324533542371).

The spelling of 14213121411130 in words is "fourteen trillion, two hundred thirteen billion, one hundred twenty-one million, four hundred eleven thousand, one hundred thirty".

Divisors: 1 2 5 10 441569 883138 2207845 3218777 4415690 6437554 16093885 32187770 1421312141113 2842624282226 7106560705565 14213121411130