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14213141212003 = 437113151354001
BaseRepresentation
bin1100111011010100000100…
…1110111010101101100011
31212022202121020201101011121
43032311001032322231203
53330332003122241003
650121232114553111
72664602613641026
oct316650116725543
955282536641147
1014213141212003
11458a839750978
121716728298797
137c13a79879c6
14371cc39571bd
15199ab2db9cbd
hexced413bab63

14213141212003 has 16 divisors (see below), whose sum is σ = 14749683075072. Its totient is φ = 13685994000000.

The previous prime is 14213141211977. The next prime is 14213141212027. The reversal of 14213141212003 is 30021214131241.

It is a cyclic number.

It is not a de Polignac number, because 14213141212003 - 29 = 14213141211491 is a prime.

It is a super-2 number, since 2×142131412120032 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14213141212093) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 39973003 + ... + 40327003.

It is an arithmetic number, because the mean of its divisors is an integer number (921855192192).

Almost surely, 214213141212003 is an apocalyptic number.

14213141212003 is a deficient number, since it is larger than the sum of its proper divisors (536541863069).

14213141212003 is a wasteful number, since it uses less digits than its factorization.

14213141212003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 367266.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 14213141212003 its reverse (30021214131241), we get a palindrome (44234355343244).

The spelling of 14213141212003 in words is "fourteen trillion, two hundred thirteen billion, one hundred forty-one million, two hundred twelve thousand, three".

Divisors: 1 43 71 3053 13151 354001 565493 933721 15222043 25134071 40150003 1080765053 4655467151 200185087493 330538167721 14213141212003