Base | Representation |
---|---|
bin | 1100111011010100000100… |
… | …1110111010101101100011 |
3 | 1212022202121020201101011121 |
4 | 3032311001032322231203 |
5 | 3330332003122241003 |
6 | 50121232114553111 |
7 | 2664602613641026 |
oct | 316650116725543 |
9 | 55282536641147 |
10 | 14213141212003 |
11 | 458a839750978 |
12 | 1716728298797 |
13 | 7c13a79879c6 |
14 | 371cc39571bd |
15 | 199ab2db9cbd |
hex | ced413bab63 |
14213141212003 has 16 divisors (see below), whose sum is σ = 14749683075072. Its totient is φ = 13685994000000.
The previous prime is 14213141211977. The next prime is 14213141212027. The reversal of 14213141212003 is 30021214131241.
It is a cyclic number.
It is not a de Polignac number, because 14213141212003 - 29 = 14213141211491 is a prime.
It is a super-2 number, since 2×142131412120032 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14213141212093) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 39973003 + ... + 40327003.
It is an arithmetic number, because the mean of its divisors is an integer number (921855192192).
Almost surely, 214213141212003 is an apocalyptic number.
14213141212003 is a deficient number, since it is larger than the sum of its proper divisors (536541863069).
14213141212003 is a wasteful number, since it uses less digits than its factorization.
14213141212003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 367266.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 14213141212003 its reverse (30021214131241), we get a palindrome (44234355343244).
The spelling of 14213141212003 in words is "fourteen trillion, two hundred thirteen billion, one hundred forty-one million, two hundred twelve thousand, three".
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