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14213141212093 is a prime number
BaseRepresentation
bin1100111011010100000100…
…1110111010101110111101
31212022202121020201101021221
43032311001032322232331
53330332003122241333
650121232114553341
72664602613641215
oct316650116725675
955282536641257
1014213141212093
11458a839750a4a
121716728298851
137c13a7987a65
14371cc3957245
15199ab2db9d2d
hexced413babbd

14213141212093 has 2 divisors, whose sum is σ = 14213141212094. Its totient is φ = 14213141212092.

The previous prime is 14213141212079. The next prime is 14213141212097. The reversal of 14213141212093 is 39021214131241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13767201734724 + 445939477369 = 3710418^2 + 667787^2 .

It is a cyclic number.

It is not a de Polignac number, because 14213141212093 - 237 = 14075702258621 is a prime.

It is a super-3 number, since 3×142131412120933 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14213141212097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106570606046 + 7106570606047.

It is an arithmetic number, because the mean of its divisors is an integer number (7106570606047).

Almost surely, 214213141212093 is an apocalyptic number.

It is an amenable number.

14213141212093 is a deficient number, since it is larger than the sum of its proper divisors (1).

14213141212093 is an equidigital number, since it uses as much as digits as its factorization.

14213141212093 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10368, while the sum is 34.

The spelling of 14213141212093 in words is "fourteen trillion, two hundred thirteen billion, one hundred forty-one million, two hundred twelve thousand, ninety-three".