Base | Representation |
---|---|
bin | 11010011110010111… |
… | …00100010111100001 |
3 | 1100200112220012111012 |
4 | 31033023210113201 |
5 | 213102103200442 |
6 | 10310213030305 |
7 | 1012135230665 |
oct | 151713442741 |
9 | 40615805435 |
10 | 14213334497 |
11 | 603406963a |
12 | 2908025395 |
13 | 14568846cb |
14 | 98b96a8a5 |
15 | 582c23582 |
hex | 34f2e45e1 |
14213334497 has 2 divisors, whose sum is σ = 14213334498. Its totient is φ = 14213334496.
The previous prime is 14213334467. The next prime is 14213334539. The reversal of 14213334497 is 79443331241.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13840110736 + 373223761 = 117644^2 + 19319^2 .
It is an emirp because it is prime and its reverse (79443331241) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14213334497 - 210 = 14213333473 is a prime.
It is a super-2 number, since 2×142133344972 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14213334467) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106667248 + 7106667249.
It is an arithmetic number, because the mean of its divisors is an integer number (7106667249).
Almost surely, 214213334497 is an apocalyptic number.
It is an amenable number.
14213334497 is a deficient number, since it is larger than the sum of its proper divisors (1).
14213334497 is an equidigital number, since it uses as much as digits as its factorization.
14213334497 is an evil number, because the sum of its binary digits is even.
The product of its digits is 217728, while the sum is 41.
The spelling of 14213334497 in words is "fourteen billion, two hundred thirteen million, three hundred thirty-four thousand, four hundred ninety-seven".
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