Base | Representation |
---|---|
bin | 11010011110010111… |
… | …00100011000001011 |
3 | 1100200112220012112202 |
4 | 31033023210120023 |
5 | 213102103201124 |
6 | 10310213030415 |
7 | 1012135231055 |
oct | 151713443013 |
9 | 40615805482 |
10 | 14213334539 |
11 | 6034069678 |
12 | 290802540b |
13 | 1456884731 |
14 | 98b96a8d5 |
15 | 582c235ae |
hex | 34f2e460b |
14213334539 has 2 divisors, whose sum is σ = 14213334540. Its totient is φ = 14213334538.
The previous prime is 14213334497. The next prime is 14213334593. The reversal of 14213334539 is 93543331241.
14213334539 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
Together with next prime (14213334593) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14213334539 - 216 = 14213269003 is a prime.
It is not a weakly prime, because it can be changed into another prime (14213336539) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106667269 + 7106667270.
It is an arithmetic number, because the mean of its divisors is an integer number (7106667270).
Almost surely, 214213334539 is an apocalyptic number.
14213334539 is a deficient number, since it is larger than the sum of its proper divisors (1).
14213334539 is an equidigital number, since it uses as much as digits as its factorization.
14213334539 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 116640, while the sum is 38.
The spelling of 14213334539 in words is "fourteen billion, two hundred thirteen million, three hundred thirty-four thousand, five hundred thirty-nine".
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