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142134103 is a prime number
BaseRepresentation
bin10000111100011…
…00101101010111
3100220110011100001
420132030231113
5242341242403
622034232131
73344056066
oct1036145527
9326404301
10142134103
117325a501
123b725647
13235a6827
1414c3c1dd
15c728c1d
hex878cb57

142134103 has 2 divisors, whose sum is σ = 142134104. Its totient is φ = 142134102.

The previous prime is 142134073. The next prime is 142134211. The reversal of 142134103 is 301431241.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 142134103 - 25 = 142134071 is a prime.

It is a super-2 number, since 2×1421341032 = 40404206471229218, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (142144103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71067051 + 71067052.

It is an arithmetic number, because the mean of its divisors is an integer number (71067052).

Almost surely, 2142134103 is an apocalyptic number.

142134103 is a deficient number, since it is larger than the sum of its proper divisors (1).

142134103 is an equidigital number, since it uses as much as digits as its factorization.

142134103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 19.

The square root of 142134103 is about 11922.0007968461. Note that the first 3 decimals coincide. The cubic root of 142134103 is about 521.8745251672.

Subtracting from 142134103 its sum of digits (19), we obtain a square (142134084 = 119222).

Adding to 142134103 its reverse (301431241), we get a palindrome (443565344).

The spelling of 142134103 in words is "one hundred forty-two million, one hundred thirty-four thousand, one hundred three".