14213423004041 has 2 divisors, whose sum is σ = 14213423004042. Its totient is φ = 14213423004040.

The previous prime is 14213423003957. The next prime is 14213423004043. The reversal of 14213423004041 is 14040032431241.

14213423004041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12588154984441 + 1625268019600 = 3547979^2 + 1274860^2 .

It is a cyclic number.

It is not a de Polignac number, because 14213423004041 - 2³⁸ = 13938545097097 is a prime.

Together with 14213423004043, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 14213423003995 and 14213423004013.

It is not a weakly prime, because it can be changed into another prime (14213423004043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106711502020 + 7106711502021.

It is an arithmetic number, because the mean of its divisors is an integer number (7106711502021).

Almost surely, 2^{14213423004041} is an apocalyptic number.

It is an amenable number.

14213423004041 is a deficient number, since it is larger than the sum of its proper divisors (1).

14213423004041 is an equidigital number, since it uses as much as digits as its factorization.

14213423004041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9216, while the sum is 29.

Adding to 14213423004041 its reverse (14040032431241), we get a palindrome (28253455435282).

The spelling of 14213423004041 in words is "fourteen trillion, two hundred thirteen billion, four hundred twenty-three million, four thousand, forty-one".