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142135511503 is a prime number
BaseRepresentation
bin1000010001011111101…
…1111100100111001111
3111120212200001002210211
42010113323330213033
54312043142332003
6145143545143251
713161151625236
oct2042773744717
9446780032724
10142135511503
1155308877587
1223668a8ab27
131053213467b
146c450bdb1d
153a6d45096d
hex2117efc9cf

142135511503 has 2 divisors, whose sum is σ = 142135511504. Its totient is φ = 142135511502.

The previous prime is 142135511461. The next prime is 142135511519. The reversal of 142135511503 is 305115531241.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-142135511503 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (142135511563) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71067755751 + 71067755752.

It is an arithmetic number, because the mean of its divisors is an integer number (71067755752).

Almost surely, 2142135511503 is an apocalyptic number.

142135511503 is a deficient number, since it is larger than the sum of its proper divisors (1).

142135511503 is an equidigital number, since it uses as much as digits as its factorization.

142135511503 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9000, while the sum is 31.

The spelling of 142135511503 in words is "one hundred forty-two billion, one hundred thirty-five million, five hundred eleven thousand, five hundred three".