Base | Representation |
---|---|
bin | 11010011110011011… |
… | …11110111010000111 |
3 | 1100200121002100210120 |
4 | 31033031332322013 |
5 | 213102233424440 |
6 | 10310234353023 |
7 | 1012143505320 |
oct | 151715767207 |
9 | 40617070716 |
10 | 14213967495 |
11 | 6034461182 |
12 | 290828b773 |
13 | 1456a46870 |
14 | 98ba93447 |
15 | 582ceadd0 |
hex | 34f37ee87 |
14213967495 has 128 divisors (see below), whose sum is σ = 29843251200. Its totient is φ = 5605908480.
The previous prime is 14213967491. The next prime is 14213967557. The reversal of 14213967495 is 59476931241.
It is a happy number.
It is not a de Polignac number, because 14213967495 - 22 = 14213967491 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (51).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14213967491) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 3455490 + ... + 3459600.
It is an arithmetic number, because the mean of its divisors is an integer number (233150400).
Almost surely, 214213967495 is an apocalyptic number.
14213967495 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
14213967495 is an abundant number, since it is smaller than the sum of its proper divisors (15629283705).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14213967495 is a wasteful number, since it uses less digits than its factorization.
14213967495 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4305.
The product of its digits is 1632960, while the sum is 51.
The spelling of 14213967495 in words is "fourteen billion, two hundred thirteen million, nine hundred sixty-seven thousand, four hundred ninety-five".
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