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142141021212 = 22311845085101
BaseRepresentation
bin1000010001100001000…
…0111101110000011100
3111120220001102000201010
42010120100331300130
54312101100134322
6145144303215220
713161246513441
oct2043020756034
9446801360633
10142141021212
11553109a0063
122366a8a7510
1310533313458
146c45b159c8
153a6db8d20c
hex211843dc1c

142141021212 has 12 divisors (see below), whose sum is σ = 331662382856. Its totient is φ = 47380340400.

The previous prime is 142141021181. The next prime is 142141021229. The reversal of 142141021212 is 212120141241.

It is a tau number, because it is divible by the number of its divisors (12).

It is a super-2 number, since 2×1421410212122 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5922542539 + ... + 5922542562.

Almost surely, 2142141021212 is an apocalyptic number.

142141021212 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

142141021212 is an abundant number, since it is smaller than the sum of its proper divisors (189521361644).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

142141021212 is a wasteful number, since it uses less digits than its factorization.

142141021212 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11845085108 (or 11845085106 counting only the distinct ones).

The product of its (nonzero) digits is 256, while the sum is 21.

Adding to 142141021212 its reverse (212120141241), we get a palindrome (354261162453).

The spelling of 142141021212 in words is "one hundred forty-two billion, one hundred forty-one million, twenty-one thousand, two hundred twelve".

Divisors: 1 2 3 4 6 12 11845085101 23690170202 35535255303 47380340404 71070510606 142141021212