14214113220301 has 4 divisors (see below), whose sum is σ = 14322617901504. Its totient is φ = 14105608539100.

The previous prime is 14214113220233. The next prime is 14214113220311. The reversal of 14214113220301 is 10302231141241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14214113220301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14214113220311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54252340405 + ... + 54252340666.

It is an arithmetic number, because the mean of its divisors is an integer number (3580654475376).

Almost surely, 2^{14214113220301} is an apocalyptic number.

It is an amenable number.

14214113220301 is a deficient number, since it is larger than the sum of its proper divisors (108504681203).

14214113220301 is a wasteful number, since it uses less digits than its factorization.

14214113220301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 108504681202.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 14214113220301 its reverse (10302231141241), we get a palindrome (24516344361542).

The spelling of 14214113220301 in words is "fourteen trillion, two hundred fourteen billion, one hundred thirteen million, two hundred twenty thousand, three hundred one".