Base | Representation |
---|---|
bin | 100000010100011011011011… |
… | …000100101110000001111111 |
3 | 200122021120121012111210212211 |
4 | 200110123123010232001333 |
5 | 122112320412211004442 |
6 | 1222150453345241251 |
7 | 41640241331465113 |
oct | 4024333304560177 |
9 | 618246535453784 |
10 | 142141323141247 |
11 | 41321884329831 |
12 | 13b37b35633227 |
13 | 6140b3b9b4b71 |
14 | 2715968dd1743 |
15 | 116764e44c617 |
hex | 8146db12e07f |
142141323141247 has 2 divisors, whose sum is σ = 142141323141248. Its totient is φ = 142141323141246.
The previous prime is 142141323141133. The next prime is 142141323141281. The reversal of 142141323141247 is 742141323141241.
It is a strong prime.
It is an emirp because it is prime and its reverse (742141323141241) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 142141323141247 - 27 = 142141323141119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (142141323147247) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71070661570623 + 71070661570624.
It is an arithmetic number, because the mean of its divisors is an integer number (71070661570624).
Almost surely, 2142141323141247 is an apocalyptic number.
142141323141247 is a deficient number, since it is larger than the sum of its proper divisors (1).
142141323141247 is an equidigital number, since it uses as much as digits as its factorization.
142141323141247 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 129024, while the sum is 40.
Adding to 142141323141247 its reverse (742141323141241), we get a palindrome (884282646282488).
The spelling of 142141323141247 in words is "one hundred forty-two trillion, one hundred forty-one billion, three hundred twenty-three million, one hundred forty-one thousand, two hundred forty-seven".
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