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142141998934693 is a prime number
BaseRepresentation
bin100000010100011100000011…
…010110101010101010100101
3200122021122100022010200012201
4200110130003112222222211
5122112323303211402233
61222151044410014501
741640264145600312
oct4024340326525245
9618248308120181
10142141998934693
11413220a084540a
1213b380a3a17431
136140c189ca244
1427159d0a67d09
15116768d93c77d
hex8147035aaaa5

142141998934693 has 2 divisors, whose sum is σ = 142141998934694. Its totient is φ = 142141998934692.

The previous prime is 142141998934681. The next prime is 142141998934721. The reversal of 142141998934693 is 396439899141241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 109993802010849 + 32148196923844 = 10487793^2 + 5669938^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-142141998934693 is a prime.

It is a super-2 number, since 2×1421419989346932 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (142141998934613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71070999467346 + 71070999467347.

It is an arithmetic number, because the mean of its divisors is an integer number (71070999467347).

Almost surely, 2142141998934693 is an apocalyptic number.

It is an amenable number.

142141998934693 is a deficient number, since it is larger than the sum of its proper divisors (1).

142141998934693 is an equidigital number, since it uses as much as digits as its factorization.

142141998934693 is an evil number, because the sum of its binary digits is even.

The product of its digits is 362797056, while the sum is 73.

The spelling of 142141998934693 in words is "one hundred forty-two trillion, one hundred forty-one billion, nine hundred ninety-eight million, nine hundred thirty-four thousand, six hundred ninety-three".