Base | Representation |
---|---|
bin | 100000010100011100000011… |
… | …010110101010101011111111 |
3 | 200122021122100022010200100001 |
4 | 200110130003112222223333 |
5 | 122112323303211403113 |
6 | 1222151044410015131 |
7 | 41640264145600501 |
oct | 4024340326525377 |
9 | 618248308120301 |
10 | 142141998934783 |
11 | 413220a0845491 |
12 | 13b380a3a174a7 |
13 | 6140c189ca2b3 |
14 | 27159d0a67d71 |
15 | 116768d93c7dd |
hex | 8147035aaaff |
142141998934783 has 2 divisors, whose sum is σ = 142141998934784. Its totient is φ = 142141998934782.
The previous prime is 142141998934769. The next prime is 142141998934843. The reversal of 142141998934783 is 387439899141241.
142141998934783 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 142141998934783 - 217 = 142141998803711 is a prime.
It is a super-2 number, since 2×1421419989347832 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (142141978934783) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71070999467391 + 71070999467392.
It is an arithmetic number, because the mean of its divisors is an integer number (71070999467392).
Almost surely, 2142141998934783 is an apocalyptic number.
142141998934783 is a deficient number, since it is larger than the sum of its proper divisors (1).
142141998934783 is an equidigital number, since it uses as much as digits as its factorization.
142141998934783 is an evil number, because the sum of its binary digits is even.
The product of its digits is 376233984, while the sum is 73.
The spelling of 142141998934783 in words is "one hundred forty-two trillion, one hundred forty-one billion, nine hundred ninety-eight million, nine hundred thirty-four thousand, seven hundred eighty-three".
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