Base | Representation |
---|---|
bin | 1100111011011000011100… |
… | …0101011011110110101111 |
3 | 1212022212121220220001102011 |
4 | 3032312013011123312233 |
5 | 3330341403130201224 |
6 | 50121544301142051 |
7 | 2664643634043541 |
oct | 316660705336657 |
9 | 55285556801364 |
10 | 14214313131439 |
11 | 4590290218333 |
12 | 17169b485a927 |
13 | 7c15336c9a65 |
14 | 371d95457691 |
15 | 199b30c0a394 |
hex | ced8715bdaf |
14214313131439 has 2 divisors, whose sum is σ = 14214313131440. Its totient is φ = 14214313131438.
The previous prime is 14214313131241. The next prime is 14214313131449. The reversal of 14214313131439 is 93413131341241.
It is a strong prime.
It is an emirp because it is prime and its reverse (93413131341241) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14214313131439 - 225 = 14214279577007 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14214313131449) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7107156565719 + 7107156565720.
It is an arithmetic number, because the mean of its divisors is an integer number (7107156565720).
Almost surely, 214214313131439 is an apocalyptic number.
14214313131439 is a deficient number, since it is larger than the sum of its proper divisors (1).
14214313131439 is an equidigital number, since it uses as much as digits as its factorization.
14214313131439 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 93312, while the sum is 40.
The spelling of 14214313131439 in words is "fourteen trillion, two hundred fourteen billion, three hundred thirteen million, one hundred thirty-one thousand, four hundred thirty-nine".
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