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14214412131133 is a prime number
BaseRepresentation
bin1100111011011000110011…
…1111000101101100111101
31212022212212211011202110111
43032312030333011230331
53330342104001144013
650122002155110021
72664646245401434
oct316661477055475
955285784152414
1014214412131133
114590331096265
121716a21a42311
137c154b080166
14371da466811b
15199b3976373d
hexced8cfc5b3d

14214412131133 has 2 divisors, whose sum is σ = 14214412131134. Its totient is φ = 14214412131132.

The previous prime is 14214412131121. The next prime is 14214412131203. The reversal of 14214412131133 is 33113121441241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13186789975044 + 1027622156089 = 3631362^2 + 1013717^2 .

It is a cyclic number.

It is not a de Polignac number, because 14214412131133 - 29 = 14214412130621 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14214412131095 and 14214412131104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14214412431133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7107206065566 + 7107206065567.

It is an arithmetic number, because the mean of its divisors is an integer number (7107206065567).

Almost surely, 214214412131133 is an apocalyptic number.

It is an amenable number.

14214412131133 is a deficient number, since it is larger than the sum of its proper divisors (1).

14214412131133 is an equidigital number, since it uses as much as digits as its factorization.

14214412131133 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6912, while the sum is 31.

Adding to 14214412131133 its reverse (33113121441241), we get a palindrome (47327533572374).

The spelling of 14214412131133 in words is "fourteen trillion, two hundred fourteen billion, four hundred twelve million, one hundred thirty-one thousand, one hundred thirty-three".