Base | Representation |
---|---|
bin | 1000010001100100000… |
… | …0010100000111001111 |
3 | 111120220220202122020101 |
4 | 2010121000110013033 |
5 | 4312112234333201 |
6 | 145145425231531 |
7 | 13161460151143 |
oct | 2043100240717 |
9 | 446826678211 |
10 | 142153433551 |
11 | 553179a8698 |
12 | 23672a925a7 |
13 | 10535a6b02c |
14 | 6c47627223 |
15 | 3a6ece0d01 |
hex | 21190141cf |
142153433551 has 2 divisors, whose sum is σ = 142153433552. Its totient is φ = 142153433550.
The previous prime is 142153433537. The next prime is 142153433563. The reversal of 142153433551 is 155334351241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 142153433551 - 25 = 142153433519 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 142153433551.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (142153433581) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71076716775 + 71076716776.
It is an arithmetic number, because the mean of its divisors is an integer number (71076716776).
Almost surely, 2142153433551 is an apocalyptic number.
142153433551 is a deficient number, since it is larger than the sum of its proper divisors (1).
142153433551 is an equidigital number, since it uses as much as digits as its factorization.
142153433551 is an evil number, because the sum of its binary digits is even.
The product of its digits is 108000, while the sum is 37.
Adding to 142153433551 its reverse (155334351241), we get a palindrome (297487784792).
The spelling of 142153433551 in words is "one hundred forty-two billion, one hundred fifty-three million, four hundred thirty-three thousand, five hundred fifty-one".
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